Answer:
M₁ = 0.178 M
Explanation:
In case of titration , the following formula can be used -
M₁V₁ = M₂V₂
where ,
M₁ = concentration of acid ,
V₁ = volume of acid,
M₂ = concentration of base ,
V₂ = volume of base,
from , the question ,
M₁ = ?
V₁ = 20.0 mL
M₂ = 0.158 M
V₂ = 22.60 mL
Using the above formula , the molarity of the acid , can be calculated as ,
M₁V₁ = M₂V₂
M₁ * 20.0 mL = 0.158 M * 22.60 mL
M₁ = 0.178 M
