Answer:
one solution: (-1,1)
Step-by-step explanation:
we have
[tex]y=x+2[/tex] ----> equation A
[tex]6x-4y=-10[/tex] ----> equation B
Solve the system by substitution
Substitute equation A in equation B
[tex]6x-4(x+2)=-10[/tex]
solve for x
[tex]6x-4x-8=-10[/tex]
[tex]6x-4x=-10+8[/tex]
[tex]2x=-2[/tex]
[tex]x=-1[/tex]
Find the value of y
[tex]y=x+2[/tex] ----> [tex]y=-1+2=1[/tex]
The solution is the point (-1,1)
therefore
one solution: (-1,1)
