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Determine the moment of inertia of a uniform solid sphere of mass M and radius R about an axis that is tangent to the surface of the sphere. (Use any variable or symbol stated above as necessary.)

Respuesta :

Answer:

[tex]I = \frac{7}{5}MR^2[/tex]

Explanation:

For answer this we will use the paralell axis theorem:

I= [tex]I_{cm} + Md^2[/tex]

Where [tex]I_{cm}[/tex] is the moment of inertia of the center of mass, M is the mass of the sphere and d is the distance between the center of mass and the axis for rotate, then:

[tex]I = \frac{2}{5}MR^2 +MR^2[/tex]

[tex]I = \frac{7}{5}MR^2[/tex]

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