Respuesta :
Answer : The compound contains the highest percentage of lead (by mass) is, PbS.
Explanation :
To calculate the percentage of lead in sample, we use the equation:
[tex]\%\text{ of lead}=\frac{\text{Mass of lead}}{\text{Mass of sample}}\times 100[/tex]
For [tex]PbS[/tex] :
Mass of [tex]PbS[/tex] = 239.3 g
Mass of Pb = 207.2 g
Putting values in above equation, we get:
[tex]\%\text{ of lead}=\frac{\text{Mass of lead}}{\text{Mass of sample}}\times 100=\frac{207.2g}{239.3g}\times 100=86.58\%[/tex]
The percentage of lead in the [tex]PbS[/tex] is 86.58 %.
For [tex]PbCO_3[/tex] :
Mass of [tex]PbCO_3[/tex] = 267.2 g
Mass of Pb = 207.2 g
Putting values in above equation, we get:
[tex]\%\text{ of lead}=\frac{\text{Mass of lead}}{\text{Mass of sample}}\times 100=\frac{207.2g}{267.2g}\times 100=77.55\%[/tex]
The percentage of lead in the [tex]PbCO_3[/tex] is 77.55 %.
For [tex]PbCl(OH)[/tex] :
Mass of [tex]PbCl(OH)[/tex] = 259.7 g
Mass of Pb = 207.2 g
Putting values in above equation, we get:
[tex]\%\text{ of lead}=\frac{\text{Mass of lead}}{\text{Mass of sample}}\times 100=\frac{207.2g}{259.7g}\times 100=79.78\%[/tex]
The percentage of lead in the [tex]PbCl(OH)[/tex] is 79.78 %.
For [tex]Pb_2Cl_2CO_3[/tex] :
Mass of [tex]Pb_2Cl_2CO3_[/tex] = 545.3 g
Mass of Pb = 207.2 g
Putting values in above equation, we get:
[tex]\%\text{ of lead}=\frac{\text{Mass of lead}}{\text{Mass of sample}}\times 100=\frac{207.2g}{545.3g}\times 100=37.99\%[/tex]
The percentage of lead in the [tex]Pb_2Cl_2CO3_[/tex] is 37.99 %.
Hence, from this we conclude that, the compound PbS contains the highest percentage of lead (by mass).
