Answer:
Step-by-step explanation:
[tex]\dfrac{6y-10}{5+7y}=\dfrac{1}{2}\qquad\text{cross multiply}\\\\(2)(6y-10)=(1)(5+7y)\qquad\text{use the distributive property}:\ a(b+c)=ab+ac\\\\(2)(6y)+(2)(-10)=5+7y\\\\12y-20=5+7y\qquad\text{add 20 to both sides}\\\\12y-20+20=5+20+7y\\\\12y=25+7y\qquad\text{subtract}\ 7y\ \text{from both sides}\\\\12y-7y=25+7y-7y\\\\5y=25\qquad\text{divide both sides by 5}\\\\\dfrac{5y}{5}=\dfrac{25}{5}\\\\y=5[/tex]