Respuesta :
Answer: Order with respect to A is 1 , order with respect to B is 0 and total order is 1
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
[tex]Rate=k[A]^x[B]^y[/tex]
k= rate constant
x = order with respect to A
y = order with respect to A
n = x+y = Total order
a) From trial 1: [tex]3.20\times 10^{-1}=k[1.50]^x[1.50]^y[/tex] (1)
From trial 2: [tex]3.20\times 10^{-1}=k[1.50]^x[2.50]^y[/tex] (2)
Dividing 2 by 1 :[tex]\frac{3.20\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k[1.50]^x[2.50]^y}{k[1.50]^x[1.50]^y}[/tex]
[tex]1=1.66^y,2^0=1.66^y[/tex] therefore y=0
b) From trial 2: [tex]3.20\times 10^{-1}=k[1.50]^x[2.50]^y[/tex] (3)
From trial 3: [tex]6.40\times 10^{-1}=k[3.00]^x[1.50]^y[/tex] (4)
Dividing 4 by 3:[tex]\frac{6.40\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k[3.00]^x[1.50]^y}{k[1.50]^x[2.50]^y}[/tex]
[tex]2=2^x,2^1=2^x[/tex], x=1
Thus rate law is [tex]Rate=k[A]^1[B]^0[/tex]
Thus order with respect to A is 1 , order with respect to B is 0 and total order is 1+0=1.
