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A 900 liter supply of xenon gas is held at 27 °C and 100 kPa. When the temperature is lowered to -73
C, what pressure must be applied to compress the gas to 200 liters?

Respuesta :

nkirotedoreen46

Answer:

300 kPa

Explanation:

Concept tested: Gas Laws (Combined gas law)

Initial pressure, P₁ = 100 kPa

Initial temperature,T₁ = 27°C

But, K = °C + 273, therefore, T₁ = 300 K

Initial volume, V₁ = 900 L

New temperature, T₂ = -73°C

                                   = -73°C + 273

                                   = 200 K

New volume, V₂ = 200 L             

We are required to calculate the new pressure, P₂

  • To find the new pressure of the gas, we are going to use the combined gas law;
  • Combined gas law combines both Charles's law and Boyle's law.
  • According to the combined gas law;

P₁V₁/T₁ = P₂V₂/T₂

  • To calculate the new Pressure, P₂, we rearranging the formula;

P₂ =(P₁V₁T₂) ÷ (V₂T₁)

Therefore;

P₂ = (100 kPa × 900 L × 200 K) ÷ (200 L × 300 K)

   = 300 kPa

Therefore, a pressure of 300 kPa must be applied.

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