A package is dropped from a helicopter moving upward at 15m/s. If it takes 16.0 s before the package strikes the ground, how high above the ground was the package when it was released?

Respuesta :

Answer:

Height of package initially = 1054.4 metre

Explanation:

The package is dropped from a helicopter moving upward at 15 m/s.

Total time taken for the package to reach the ground = 16 seconds.

Initially , the package has an upward velocity and therefore it moves upwards ,reaches the topmost point and then falls down and finally strikes the ground.

Displacement , h = unknown

Time , t = 16 seconds

Initial velocity , u = 16 m/s

By equation of motion ,

s = [tex]u \times t - 0.5 \times g \times t^{2}[/tex]

Acceleration ,  a = g = 9.8 m/[tex]s^{2}[/tex]

-s = [tex]15 \times 16 - 0.5\times 9.8\times (16)^{2}[/tex]

-s = 240 - 1254.4

s = 1054.4 metres