Answer : The equilibrium constant expression will be [tex]K_c=\frac{4x^3}{(0.87-x)}[/tex]
Solution :
Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.
The given equilibrium reaction is,
[tex]A_2B(g)\rightleftharpoons 2A(g)+B(g)[/tex]
Initially conc. 0.87 0 0
At equilibrium (0.87-x) 2x x
The expression of [tex]K_c[/tex] will be,
[tex]K_c=\frac{[A]^2[B]}{[A_2B]}[/tex]
[tex]K_c=\frac{(2x)^2\times (x)}{(0.87-x)}[/tex]
[tex]K_c=\frac{4x^3}{(0.87-x)}[/tex]
Therefore, the equilibrium constant expression will be [tex]K_c=\frac{4x^3}{(0.87-x)}[/tex]
