Answer:
a) 0.34 m
b) 1.0676 x 10⁻¹⁸m³
Explanation:
a.) In a DNA helix structure, each turns contains 10 base pairs, so the total number of turns in a DNA molecule with 10⁹ base pairs = 10⁹/10 =10⁸ turns.
Ideally, in-between two consecutive base pairs, the distance is usually= 0.34nm or 0.34 x 10⁻⁹m
Therefore, the length of turns in a double-stranded DNA molecule can be calculated as:
10 x 0.34 x 10⁻⁹m = 3.4 x 10⁻⁹m
As such, for 10⁸ turns the total distance or length in meters = 10⁸ x 3.4 x 10⁻⁹m = 0.34 m
b.) In order to determine the minimum volume needed to contain this Double helical DNA, we require a space similar to a Cylinder. Hence, we need to calculate the volume of that cylinder which will be the minimum volume needed to contain it.
The distance between two-strand = 2nm = 2 x 10⁻⁹m (i.e this will represent the diameter of the cylinder )
the length represent the height of the cylinder
The volume of cylinder can then be calculated as = πr²h
= 3.14 x (1 x 10⁻⁹m)² x 0.34 m
= 1.0676 x 10⁻¹⁸m³
