mass of C = 0.238 g
mass of H =0.00989 g
mass of Cl = 1.05 g
Explanation:
Determine the masses of carbon, hydrogen, and chlorine in the original sample of the solvent.
First we need to calculate the molar mass of carbon dioxide (CO₂) and water (H₂O)
molar mass of CO₂ = molar mass of C × 1 + molar mass of O × 2
molar mass of CO₂ = 12 × 1 + 16 × 2 = 44 g/mole
molar mass of H₂O = molar mass of H × 2 + molar mass of O × 1
molar mass of H₂O = 1 × 2 + 16 × 1 = 18 g/mole
Now, to find the mass of carbon and hydrogen in the original sample of solvent, we devise the following reasoning:
if 44 g of CO₂ contains 12 g of C
then 0.872 g of CO₂ contains X g of C
X = (0.872 × 12) / 44 = 0.238 g of C
if 18 g of H₂O contains 2 g of H
then 0.089 g of H₂O contains Y g of H
Y = (0.089 × 2) / 18 = 0.00989 g of H
And now, we can find the mass of chlorine:
mass of sample = mass of C + mass of H + mass of Cl
mass of Cl = mass of sample - mass of C - mass of H
mass of Cl = 1.30 - 0.238 - 0.00989
mass of Cl = 1.05 g
Learn more about:
combustion reaction
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