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Professional Application. A 98 kg football player catches a 0.750 kg ball with his feet off the ground with both of them moving horizontally. The player's speed is 5.35 m/s, and the ball's speed is 25.9 m/s. (a) First, consider the situation where the player and the ball are going in the same direction, and take this direction as positive. Calculate their final velocity (in m/s).

Respuesta :

Answer:

[tex]V_s = 5.5 m/s[/tex]  

Explanation:

a)

We will use the conservation of the linear momentum:

[tex]P_i =P_f[/tex]

so:

[tex]M_pV_p +M_bV_b = M_sV_s[/tex]

Where [tex]M_p[/tex] is the mass of the football player, [tex]V_p[/tex] is the velocity of the football player, [tex]M_b[/tex] is the mass of the ball,[tex]V_b[/tex] is velocity of the ball, [tex]M_s[/tex] is the mass of both after the collition and [tex]V_s[/tex] is the Velocity of both after the collition.

[tex](98 kg)(5.35 m/s) +(0.750 kg)(25.9 m/s) = (98 kg + 0.750 kg)V_s[/tex]

Solving for [tex]V_s[/tex], we get:

[tex]V_s = 5.5 m/s[/tex]

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