Answer:
Explanation:
Assuming Dinitrogen difluoride behaves ideally, we can use PV=nRT to solve the problem:
0.170 atm * 25.0 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 295.16K
With the number of moles of dinitrogen difluoride we can calculate the mass, using its molar mass:
0.176 mol * 66 g/mol = 11.616 g