The power wasted as heat is C) 27.5 W
Explanation:
The efficiency of a device is defined as
[tex]\eta = \frac{P_{out}}{P_{in}}\cdot 100[/tex]
where
[tex]P_{out}[/tex] is the useful power in output
[tex]P_{in}[/tex] is the power in input
For the tv in this problem, we have
[tex]P_{in} = 110 W[/tex]
[tex]\eta = 75[/tex] (efficiency is 75%)
Therefore, the useful output power is
[tex]P_{out} = \frac{\eta}{100}P_{in} = \frac{75}{100}(110)=82.5 W[/tex]
And so, the power wasted as heat is the difference between the power in input and the useful power in output:
[tex]P_{heat}=P_{in} - P_{out}=110-82.5=27.5 W[/tex]
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