The solution to the system is [tex](\frac{-16}{5},\frac{-64}{5})[/tex]
Step-by-step explanation:
Given equations are;
y+x= -11 Eqn 1
y=4x+5 Eqn 2
Putting value of y from Eqn 2 in Eqn 1
[tex](4x+5)+x=-11\\4x+5+x=-11\\5x=-11-5\\5x=-16[/tex]
Dividing both sides by 5
[tex]\frac{5x}{5}=\frac{-16}{5}\\\\x=\frac{-16}{5}[/tex]
Putting in Eqn 2;
[tex]y=4(\frac{-16}{5})+5\\\\y=\frac{-64}{5}+5[/tex]
Taking LCM
[tex]y=\frac{-64+25}{5}\\\\y=\frac{-39}{5}[/tex]
The solution to the system is [tex](\frac{-16}{5},\frac{-64}{5})[/tex]
Keywords: linear equation, substitution method
Learn more about substitution method at:
- brainly.com/question/5723059
- brainly.com/question/5639299
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