Elements 36 and 54 have similar chemical properties. Based on their electronic configurations, predict the atomic number of a heavier element that should also share these chemical properties. Express your answer as an integer.

Respuesta :

Answer: The heavier element with similar chemical properties has an atomic number of 85

Explanation: Following the rule shown in the figure attached.

The electronic configuration of the element with atomic number if 35 is

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p5.

Valence shell shows that the element belongs to halogen group that requires one electron to reach the octet electronic configuration .

Also, the electronic configuration of the element with atomic number 53 is

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5

Which shows it is also an halogen with valence shell requiring one electron to complete the octect electronic configuration.

The next element must end with 6p5 and the full electronic configuration of the element

1s2 2s2 2p6 3s2 3p6 3d 10 4s2 4p6 4d10 5s2 5p6 4f14 5d10 6s2 6p5 . Summing up the electron it gives 85.

Therefore the heavier element with similar chemical properties has atomic number of 85

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Answer:

86  

Explanation:

The electron configuration of element 36 is

1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶

Now, we add 18 electrons to reach element 54. Its electron configuration is

1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶

These elements have similar properties because their electron configurations end in p⁶.

To reach the next element with similar properties, we must add enough electrons to reach a p⁶ configuration.

We follow the Wiswesser diagram below to determine the sequence order of the subshells.

To reach a p⁶ configuration, we must add 32 electrons, because we must fill the 4f orbitals.

The electron configuration of the next element with similar properties is  

1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²5d¹⁰4f¹⁴6p⁶

And the element number is 54 + 32 = 86.  

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