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A solid box made from a material whose density is rhoS floats with two thirds of its volume submerged in a liquid whose density is rhoL. How do the two densities compare?

Respuesta :

Manetho

Answer:

[tex]\frac{\rho_S}{\rho_L} = \frac{2}{3}[/tex]

Explanation:

density of the solid box material = [tex]\rho_s[/tex]

density of the liquid material = [tex]\rho_L[/tex]

Given that

solid box floats with two thirds of its volume submerged in a liquid

let V be the volume of the box

then,

[tex]V\rho_sg= \frac{2V}{3}\rho_L g[/tex]

⇒[tex]\frac{\rho_S}{\rho_L} = \frac{2}{3}[/tex]

so, the ratio of densities of solid and and the liquid is 2/3

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