Answer:
The pressure of the gas is 2.11 atm.
Explanation:
From the given,
[tex]V_{1}=1.00\,L[/tex]
[tex]P_{1}=1\,atm[/tex]
[tex]P_{2}=?[/tex]
[tex]V_{2}=473\,ml=0.473\,L[/tex]
[tex]P_{1}V_{1}=P_{2}V_{2}[/tex]
[tex](1)(1)=(0.473)(P_{2})[/tex]
[tex]P_{2}=\frac{(1)(1)}{0.473}=2.11[/tex]
Therefore, The pressure of the gas is 2.11 atm.
