Answer:
0.5987,0.3151,0.9885,0.0115
Step-by-step explanation:
Given that a manufacturing company regularly conducts quality control checks at specified periods on the products it manufactures. Historically, the failure rate for LED light bulbs that the company manufactures is 5%
Let X be the no of defectives in the sample of 10
X is binomial since each bulb is independent of the other and there are only two outcomes
P(X=x) = [tex]10Cx (0.05)^x (0.95)^{10-x}[/tex]
Using the above we calculate
a) P(X=0) = [tex]0.95^{10} =0.5987[/tex]
b) P(X=1) [tex]=0.3151[/tex]
c) [tex]P(X\leq 2) = 0.9885[/tex]
d) [tex]P(X\geq 3) = 1-0.9885\\=0.0115[/tex]