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As a way of determining the inductance of a coil used in a research project, a student first connects the coil to a 11.5 V battery and measures a current of 0.620 A. The student then connects the coil to a 24.0 V (rms), 60.0 Hz generator and measures an rms current of 0.570 A. What is the inductance?L = mH

Respuesta :

Answer:

L = 100.24 mH

Explanation:

Given that

V= 11.5 V

I= 0.62 A

V(rms) = 24 V

f= 60 Hz

I(rms) = 0.57 A

resistance R

V= I R

11.5 = 0.62 R

R= 18.54 ohm

impedance Z given

V(rms) =  I(rms) Z

24 = 0.57 Z  ,Z= 42.10 ohm

inductor  impedance  [tex]X_L[/tex]

[tex]X_L=\sqrt{Z^2-R^2}[/tex]

[tex]X_L=\sqrt{42.10^2-18.54^2}[/tex]

[tex]X_L=37.79[/tex]

 [tex]X_L=2\pi f L[/tex]

[tex]L=\dfrac{X_L}{2\pi f}[/tex]

[tex]L=\dfrac{37.79}{2\pi \times 60}[/tex]

L= 0.10024 H

L = 100.24 mH

This is the inductance .

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