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Potassium and nitrogen react in a combination reaction to produce potassium nitride: 6 K(s)+N2(g) → 2 K3N(s) How many moles of potassium are needed to produce 12.0 mol of K3N when the reaction is carried out in the presence of excess nitrogen?

Respuesta :

Answer:

Moles of potassium needed = 36 moles

Explanation:

Moles of [tex]K_3N[/tex] produced = 12.0 mol

According to the given reaction:-

[tex]6 K_{(s)}+N_2_{(g)}\rightarrow 2K_3N_{(s)}[/tex]

2 moles of [tex]K_3N[/tex] are produced when 6 moles of potassium undergoes reaction.

Also,

1 mole of [tex]K_3N[/tex] are produced when 6/2 moles of potassium undergoes reaction.

So,

12 mole of [tex]K_3N[/tex] are produced when 3*12 moles of potassium undergoes reaction.

Moles of potassium needed = 36 moles

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