Answer:
The required probability is, [tex]\frac {1}{6}[/tex]
Step-by-step explanation:
P(A sandwich is made of roast beef) = [tex]\frac {1}{2}[/tex]
P(A snack is made of popcorn) = [tex]\frac {1}{3}[/tex]
Since, the two events, i. e., 'A sandwich is made of roast beef' and 'A snack is made of popcorn' are independent, so,
P(Gretchen will get a roast beef sandwich and popcorn in her box)
= [tex]\frac {1}{2} \times \frac {1}{3}[/tex]
= [tex]\frac {1}{6}[/tex]
Answer:
The probability is 1/6
Step-by-step explanation:
Let's define the following events:
A: get a roast beef sandwich.
B: get popcorn.
Given there are 2 possible sandwiches (bologna or roast beef), P(A) = 1/2
Given there are 3 possible snacks (chips, popcorn, or pretzels), P(B) = 1/3
These events are independent, then:
P(A ∩ B) = P(A) * P(B) = 1/2 * 1/3 = 1/6
where P(A ∩ B) means Gretchen gets both a roast beef sandwich and popcorn.
