Answer:
The K.E of the neutron is, K.E = 5.025 x 10⁻²⁰ J
Explanation:
Given data,
The mass of the neutron, m = 1.675 x 10⁻²⁷ kg
The velocity of the neutron, v = 20.5% of c
The speed of light, c = 3 x 10⁸ m/s
v = 20.5% of c
= 3 x 10⁸ x 20 / 100
= 6 x 10⁷ m/s
The K.E of the neutron is,
K.E = ½ mv²
= ½ x 1.675 x 10⁻²⁷ x 6 x 10⁷
= 5.025 x 10⁻²⁰ J
Hence, the K.E of the neutron is, K.E = 5.025 x 10⁻²⁰ J
