Answer:
(a.) Density of the object = 3.941 × 10³ kg/m³ = 3941 kg/m³
(b.) Density of oil = 529 kg/m³
Explanation:
Relative density = Density of a substance/ density of water.
According to Archimedes's principal: It states that when a body is wholly or partly immersed in a liquid or fluid, it experience a loss in weight which is equal to the upthrust.
According to Archimedes's principal,
Relative density = weight in air (N)/Apparent loss of weight under water (N).
∴ Density of a object/ Density of water = Weight of object in air/apparent loss of weight under water (Upthrust in water).
(a.)
where, Density of water = 1000kg/m³, weight of object in air = 335 N
Apparent loss of weight under water (upthrust in water) = 335- 250 =85N
∴ Density of the object = (weight of object in air/loss of weight under water)× density of water.
Density of the object = (335/85) × 1000 = 3.941 × 10³ kg/m³.
Density of the object = 3.941 × 10³ kg/m³.
(b.) Relative density of oil = Density of oil/Density of water.
From Archimedes's principal,
Relative density = Upthrust of the body in oil/ Upthrust of the body in water.
Upthrust in oil = 335 - 290 = 45 N,
Upthrust in water = 85 N.,
Density of water = 1000 kg/m³
∴ Density of oil = (upthrust in oil/ upthrust in water) × density of water
Density of oil = (45/85) × 1000 = 0.529 × 1000
Density of oil = 529 kg/m³
