Respuesta :
Answer:
Value of [tex]Q_{p}[/tex] for the given redox reaction is [tex]1.0\times 10^{-8}[/tex]
Explanation:
Redox reaction with states of species:
[tex]14H^{+}(aq.)+Cr_{2}O_{7}^{2-}(aq.)+6Cl^{-}(aq.)\rightarrow 2Cr^{3+}(aq.)+3Cl_{2}(g)+7H_{2}O(l)[/tex]
Reaction quotient for this redox reaction:
[tex]Q_{p}=\frac{[Cr^{3+}]^{2}.P_{Cl_{2}}^{3}}{[H^{+}]^{14}.[Cr_{2}O_{7}^{2-}].[Cl^{-}]^{6}}[/tex]
Species inside third braket represent concentration in molarity, P represent pressure in atm and concentration of [tex]H_{2}O[/tex] is taken as 1 due to the fact that [tex]H_{2}O[/tex] is a pure liquid.
[tex]pH=-log[H^{+}][/tex]
So, [tex][H^{+}]=10^{-pH}[/tex]
Plug in all the given values in the equation of [tex]Q_{p}[/tex]:
[tex]Q_{p}=\frac{(0.10)^{2}\times (0.010)^{3}}{(10^{-0.0})^{14}\times (1.0)\times (1.0)^{6}}=1.0\times 10^{-8}[/tex]
