Answer:
The magnitude of the tension is less than the object's weight
Explanation:
As per the question:
From Fig. 1
The forces and the acceleration are shown in the figure
Since, the elevator slows down in its upward motion, this means that the final velocity is less than the initial velocity and the elevator decelerates.
Therefore, we take the acceleration as negative, '- a'.
Thus
Balancing the forces:
T - mg = m(- a)
T = mg - ma = m(g - a)
Thus it clearly shows T < mg
The magnitude of the tension in the string when the lift is moving up is equal to m(g-a).
We know that when the lift is moving upwards the acceleration of the lift can be given as (g-a), where a is the acceleration of the lift when there is no gravity and g is the acceleration due to gravity. since the lift is moving in the opposite direction of gravity the acceleration of the lift, therefore, it will be given as (g-a).
[tex]\sum F_y = 0[/tex]
T = m(g-a)
Hence, the magnitude of the tension in the string when the lift is moving up is equal to m(g-a).
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