Respuesta :

nkirotedoreen46

Answer:

212 g Na₂CO₃

Explanation:

We are given;

  • Volume of Na₂CO₃ solution as 500 mL
  • Molarity of Na₂CO₃ solution as 4.00 M

We are required to calculate the mass of Na₂CO₃.

We need to know how molarity is calculated.

  • Molarity is the concentration of a solution in moles per liter.
  • Molarity = Number of moles of solute ÷ Volume of the solution

Step 1: we calculate the number of moles of Na₂CO₃

Moles = Molarity × Volume

Therefore;

Moles of Na₂CO₃ = 4.00 M × 0.5 L

                             = 2 moles

Thus, moles of Na₂CO₃ is 2 moles

Step 2: Calculate the mass of Na₂CO₃

We need to know the relationship between the mass of a compound, molar mass and the number of moles.

Moles = Mass ÷ molar mass

Rearranging the formula;

Mass = Moles × molar mass

Molar mass of Na₂CO₃ is 106 g/mol

Therefore;

Mass of Na₂CO₃ = 2 moles × 106 g/mol

                          = 212 g

Therefore, the mass of Na₂CO₃ that would be needed is 212 g

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