Answer:
Vapour pressure of the solution is 30.5 torr.
Explanation:
[tex]\eta _{Benzene}= 2.15[/tex]
[tex]\eta _{Toulene}= 8.53[/tex]
[tex]\chi _{Benzene}= \frac{\eta_{Benzene}}{\eta_{Toulene}}= \frac{2.15}{(8.53+2.15)}=0.2013[/tex]
[tex]\chi _{Total}= \frac{8.53}{(8.53+2.15)}=0.7987[/tex]
[tex]\rho _{Benzene}= \chi_{Benzene}+\rho^{o}_{Benene}= 0.2013\times 96torr=19.32torr[/tex]
[tex]\rho _{total}= \chi_{Total}+\rho^{o}_{Total}= 0.7987\times 14torr=11.18torr[/tex]
[tex]\rho _{total}= \rho_{Benzene}+\rho_{Total}=19.32+11.18=30.5torr[/tex]
Therefore, Vapour pressure of the solution is 30.5 torr.