Answer
given,
height of the dam = 15 m
effective area of water = 2.3 x 10⁻³ m²
Using energy conservation
[tex]m g h = \dfrac{1}{2}mv^2[/tex]
[tex]v= \sqrt{2gh}[/tex]
[tex]v= \sqrt{2\times 9.8 \times 15}[/tex]
[tex]v= \sqrt{294}[/tex]
v = 17.15 m/s
discharge of water
Q = A V
Q = 2.3 x 10⁻³ x 17.15
Q = 0.039 m³/s
