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In a two-slit interference experiment, the path length to a certain point P on the screen differs for one slit in comparison with the other by 1.25λ.What is the phase difference between the two waves arriving at point P?

Respuesta :

Answer:

δ = 2.5 π

Explanation:

Given that

d= 1.25 λ

d= Path length

We know that phase difference(δ) given as

[tex]\delta =2\pi \dfrac{dsin\theta}{\lambda}[/tex]

[tex]dsin\theta = 1.25\lambda[/tex]

Now by putting the value

[tex]\delta =2\pi \dfrac{dsin\theta}{\lambda}[/tex]

[tex]\delta =2\pi \dfrac{1.25\lambda}{\lambda}[/tex]

δ = 2.5 π

Therefore the phase difference will be 2.5π

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