Answer:
(a) λ= 0.603m
(b) v= 50.8329[tex]m/s[/tex]
(c) [tex]f_{o}=14.042Hz[/tex]
Explanation:
(a)The string is an open pipe and five loops indicates that the wave forms three complete cycle in the string.
A circle represents 1 wavelength. The loops occupy the whole length of the pipe, hence;
3λ = 1.81m
λ= [tex]\frac{1.81}{3}[/tex]
λ= 0.603m
(b) speed(v) = fλ
v= 84.3 * 0.603
v= 50.8329[tex]m/s[/tex]
(c) The string represents an open pipe.for an open pipe, the fundamental frequency is [tex]f_{o}=\frac{v}{2L}[/tex]
[tex]f_{o}=14.042Hz[/tex]
