Respuesta :
Explanation:
It is known that relation between osmotic pressure and temperature is as follows.
[tex]\pi = MRT[/tex]
where, [tex]\pi[/tex] = osmotic pressure
M = molarity of solution
R = gas constant
T = Temperature in Kelvin
The given data is as follows.
[tex]\pi[/tex] = 63.0 bar, T = (20 + 273) K = 293 K
R = 0.0831 L bar/mol K
Therefore, putting the given data into the above formula as follows.
[tex]\pi = MRT[/tex]
or, M = [tex]\frac{\pi}{RT}[/tex]
M = [tex]\frac{63.0 bar}{0.0831 L bar/mol K \times 293 K}[/tex]
= 2.58 mol/L
Now, [tex]M_{1} = M_{c}[/tex] = 1.10 M, M = 2.58 M
[tex]V_{1}[/tex] = ?, [tex]V_{2} = V_{1} - 45.8 L[/tex]
As, [tex]M_{1}V_{1} = M_{2}V_{2}[/tex]
[tex]1.10 \times V_{1} = 2.58 (V_{1} - 45.8 L)[/tex]
[tex]1.10V_{1} = 2.58V_{1} - 118.16[/tex]
[tex]-1.48V_{1}[/tex] = -118.16
[tex]V_{1}[/tex] = 79.83 L
Thus, we can conclude that the required volume of seawater is 79.83 L.
