The equation of line passing through given points is:
[tex]y = -\frac{2}{3}x-\frac{7}{3}[/tex]
Step-by-step explanation:
Given points are:
(x1,y1) = (-2,-1)
(x2,y2) = (1,-3)
First of all we have to find the slope
[tex]m = \frac{y_2-y_1}{x_2-x_1}\\=\frac{-3+1}{1+2}\\=\frac{-2}{3}[/tex]
slope-intercept form of equation is:
[tex]y= mx+b[/tex]
Putting the value of slope
[tex]y = -\frac{2}{3}x+b[/tex]
Putting (1,-3) in the equation
[tex]-3 = -\frac{2}{3}(1)+b\\-3 = -\frac{2}{3}+\\b= -3+\frac{2}{3}\\b = \frac{-9+2}{3}\\b = -\frac{7}{3}[/tex]
Putting the value of b in the equation
[tex]y = -\frac{2}{3}x-\frac{7}{3}[/tex]
Hence,
The equation of line passing through given points is:
[tex]y = -\frac{2}{3}x-\frac{7}{3}[/tex]
Keywords: Equation of line, slope
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