Mindy's class will need 10 vans and 5 buses to transport everyone.
Step-by-step explanation:
No. of students = 150
Students each van can hold = 8
Students each bus can hold = 14
Number of drivers = 15
Let,
No. of vans = x
No. of buses = y
According to given statement;
x+y=15 Eqn 1
8x+14y=150 Eqn 2
Multiplying Eqn 1 by 8
[tex]8(x+y=15)\\8x+8y=120\ \ \ Eqn\ 3\\[/tex]
Subtracting Eqn 3 from Eqn 2
[tex](8x+14y)-(8x+8y)=150-120\\8x+14y-8x-8y=30\\6y=30[/tex]
Dividing both sides by 6
[tex]\frac{6y}{6}=\frac{30}{6}\\y=5[/tex]
Putting in Eqn 1
[tex]x+5=15\\x=15-5\\x=10[/tex]
Mindy's class will need 10 vans and 5 buses to transport everyone.
Keywords: linear equations, subtraction
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