Respuesta :

Answer: Tom's solution is incorrect.

Step-by-step explanation:

When you add 3/6 + 1/2 it equals ?.

3 + 1  = ?

6 + 2 = ?

We must have common denominators to do this problem.

So we must have 6 as our common denominator.

So 2 x 3 = 6. But we have to do the same to the Numerator.

So 1 x 3 = 3.

Now our problem is 3/6 + 3/6 = ?

3 + 3 = 6/6. Or 1

1 does not equal 4/12 or 1/3. So it makes it Incorrect.

What you should say:

Tom is incorrect, it is because 3/6 + 1/2 = 1, 1 does not equal 4/12 or 1/3. So, it makes it reasonable for the correct answer to be Incorrect

gmany

Answer:

[tex]\large\text{Tim's solution is incorrect,}\\\text{ because}\ \dfrac{3}{6}+\dfrac{1}{2}=1\neq\dfrac{4}{12}[/tex]

Step-by-step explanation:

[tex]\dfrac{3}{6}+\dfrac{1}{2}\\\\\text{We can simplify}\ \dfrac{3}{6}\ \text{by 3}:\ \dfrac{3}{6}=\dfrac{3:3}{6:3}=\dfrac{1}{2}\\\\\text{Therefore}\\\\\dfrac{3}{6}+\dfrac{1}{2}=\dfrac{1}{2}+\dfrac{1}{2}=\dfrac{1+1}{2}=\dfrac{2}{2}=1[/tex]

[tex]\text{What mistake could Tim make?}[/tex]

[tex]\dfrac{3}{6}+\dfrac{1}{2}=\dfrac{3+1}{6\cdot2}=\dfrac{4}{12}[/tex]

[tex]\text{or}\\\\\dfrac{3}{6}+\dfrac{1}{2}=\dfrac{3}{6\cdot2}+\dfrac{1}{2\cdot6}=\dfrac{3}{12}+\dfrac{1}{12}=\dfrac{3+1}{12}=\dfrac{4}{12}[/tex]

[tex]\text{Tim incorrectly expanded the fractions, when he transform them to}\\\text{ a common denominator.}[/tex]

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