Respuesta :
Answer:
1.58 M
Explanation:
[tex]H_2SO_4[/tex] is 1.66 m concentration.
Which means that 1.66 moles of [tex]H_2SO_4[/tex] are present in 1 kg of the solvent, water.
Mass of water = 1 kg = 1000 g
Moles of [tex]H_2SO_4[/tex] = 1.66 moles
Molar mass of [tex]H_2SO_4[/tex] = 98.079 g/mol
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]1.66\ mole= \frac{Mass}{98.079\ g/mol}[/tex]
[tex]Mass_{H_2SO_4}= 162.81114\ g[/tex]
Total mass = 1000 g + 162.81114 g = 1162.81114 g
Density = 1.104 g/mL
Volume of the solution = Mass / Density = 1162.81114 / 1.104 mL = 1053.27 mL = 1.05327 L
Considering:-
Molarity = moles/ Volume of solution = 1.66 / 1.05327 M = 1.58 M
Molar concentration of this solution will be 1.58M.
Molarity:
It is the concentration of a solution measured as the number of moles of solute per liter of solution. It is given by:
[tex]M=\frac{n}{V}[/tex]
where, n is the number of moles and V is the volume
Let's solve this:
Given:
Molar concentration of [tex]H_2SO_4[/tex] = 1.66M
Mass of water = 1 kg = 1000 g
Moles of [tex]H_2SO_4[/tex] = 1.66 moles
Molar mass of [tex]H_2SO_4[/tex] = 98.079 g/mol
Calculation for Number of moles:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} \\\\\text{Mass}= \text{Number of moles}*\text{Molar mass}\\\\\text{Mass}= 1.66 moles*98.079g/mol\\\\\text{Mass}=162.81g[/tex]
Thus, Total mass = 1000 g + 162.81 g = 1162.81 g
Given: Density = 1.104 g/mL
Calculation for Volume:
[tex]\text{Density}=\frac{\text{Mass}}{\text{Volume}}\\\\ \text{Volume}=\frac{\text{Mass}}{\text{Density}} \\\\ \text{Volume}=\frac{1162.81}{1.104}\\\\ \text{Volume}=1053.27mL[/tex]
Adding the values for number of moles and volume in the Molarity formula we will get:
[tex]M=\frac{n}{V}\\\\M=\frac{1.16}{1.05} \\\\M=1.58M[/tex]
Thus, Molar concentration of this solution will be 1.58M.
Find more information about Molarity here: brainly.com/question/14469428
