contestada

Two Earth satellites, A and B, each of mass m, are to be launched into circular orbits about Earth's center. Satellite A is to orbit at an altitude of 6390 km. Satellite B is to orbit at an altitude of 17300 km. The radius of Earth REis 6370 km. (a) What is the ratio of the potential energy of satellite B to that of satellite A, in orbit

Respuesta :

Answer:

[tex]Pa = \frac{-GMeMa}{Re}[/tex]

[tex]Pb = \frac{-GMeMb}{Re}[/tex]

where

         Pa = Gravitational potential energy of satellite A

         Pb = Gravitational potential energy of satellite B

          G = gravitational constant

          Me = Mass of the earth

          Ma = Mass of satellite A

          Mb = Mass of satellite B

          Re = Radius of the earth

Pb/Pa = (-GMeMb/Re) / (-GMeMa/Re)

Pb/Pa =  Mb/Ma

Explanation:

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