Answer:
Option A
Explanation:
Angular resolution for any optical equipment can be defined as the ability of that tool to differentiate the smallest details of the image formed.
The angular resolution is given by:
[tex]\theta_{R} = \frac{1.22\lambda}{d}[/tex] (1)
where
[tex]\theta_{R}[/tex] = Angular Resolution
[tex]\lambda [/tex] = wavelength
d = diameter of the lens
Now,
As per the question:
If the diameter of the lens is doubled, i.e., d' = 2d
Then
From eqn (1):
[tex]\theta'_{R} = \frac{1.22\lambda}{d'} = \frac{1.22\lambda}{2d}[/tex]
[tex]\theta'_{R} = \frac{1}{2}\frac{1.22\lambda}{d} = \frac{1}{2}\theta_{R}[/tex]
Thus when the diameter is doubled the angular resolution becomes half of its original value.
