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An object, moving with constant acceleration and zero initial velocity of 129 m/s how high will it be after 4.0 s

Respuesta :

josshyaby

Answer:

596m

Explanation:

S = ut + 1/2at^2

u = 129m/s, t = 4s and a = 10m/s^2

S = (129×4) + 1/2(10 × 4^2)

S = 596m

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