Answer:
a) 40.3725 N
b) [tex]a=1.729 m/s^2[/tex]
Explanation:
mass of turkey 1 M= 5 kg
mass of turkey 2 m= 3.5 kg
Let T be the tension in the string and a be the acceleration of the system
then from FBD in the attachment
T-mg=ma.................1
Mg-T=Ma..................2
from 1 and 2 we find a as
[tex]a= \frac{Mg-mg}{M+m}[/tex]
now substituting the values we get
[tex]a= \frac{5g-3.5g}{5+3.5}[/tex]
[tex]a= \frac{1.5g}{8.5}[/tex]
[tex]a=1.729 m/s^2[/tex]
now from equation 1 we can calculate Tension T as
T-mg=ma
T= m(a+g)
T= 3.5(1.729+9.81)= 40.3725 N
