Answer:
Explanation:
We can solve this exercise using uniform motion relationships.
v = d / t
The distance the Earth's orbit (Re) is 1.50 10⁸ km (10³m/1km)= 1.50 10¹¹ m. If we assume that the Earth's orbit is circular in the six months, there is a diameter whereby the distance traveled is
d = 2 Re
Let's reduce time to units Yes
t = 22 min (60s / 1 min)
t = 1320 s
Let's calculate
v = 2 1.50 10¹¹/1320
v = 2.27 10⁸ m / s
A closer value can be found if Jupiter's movement is taken into account