Answer:
In the case, the temperature required to increase the volume is 40.5 °C.
Explanation:
Charles Law:
At a constant pressure, the volume of a gas is proportional to its temperature. It is expressed as
V₁ / T₁ = V₂ / T₂ ----- (1)
where V₁ T₁ are initial volume and temperature of the gas and V₂ T₂ are the final volume and temperature of the gas.
Given data:
V₁ = 2 L
T₁ = 27 °C
V₂ = 3 L
T₂ = ?
Sol:
Using equation (1)
V₁ / T₁ = V₂ / T₂
Rearranging the above equation we get,
T₂ = V₂ x (T₁ / V₁ )
Now Putting the values of V₁ , T₁ and V₂ in above equation:
T₂ = 3 x (27 / 2)
T₂ = 40.5 °C
