Answer:
Explanation:
For rolling up or down an incline plane , the acceleration or deceleration of the rolling body is given by the following expression
a = g sinθ / (1 + k²/r² )
where k is radius of gyration of rolling body and θ is angle of inclination
a = g sin15 / ( 1 + 1 ) [ for hoop k = r ]
a = 9.8 x .2588 / 2
= 1.268 m / s²
a )
Let s be the distance up to which it goes
v² = u² - 2as
0 = 3.3² - 2 x 1.268 s
s = 4.3 m
b ) Let time in going up be t₁
v = u - at₁
0 = 3.3 - 1.268 t₁
t₁ = 2.6 s
Time in going down t₂
s = 1/2 a t₂²
4.3 = .5 x 1.268 t₂²
t₂ = 2.60
Total time
= t₁ +t₂
= 2.6 + 2.6
= 5.2 s
