There are 30.4 g of oxygen.
Explanation:
We have 0.390 moles of Fe(CO)₅. To find the mass of oxygen atoms first we calculate the molar weight and mass of Fe(CO)₅.
molar weigh of Fe(CO)₅ = molar weight of iron × 1 + molar weight of C × 5 + molar weight of O × 5
molar weigh of Fe(CO)₅ = 56 × 1 + 12 × 5 + 16 × 5 = 196 g/mole
number of moles = mass / molar weight
mass = number of moles × molar weight
mass of Fe(CO)₅ = 0.38 × 196 = 74.48 g
Now we devise the following reasoning:
if in 196 g of Fe(CO)₅ there are 80 g of O
then in 74.48 g of Fe(CO)₅ there are X g of O
X = (74.48 × 80) / 196 = 30.4 g of oxygen
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