Answer:
2.297 m
Explanation:
Mass of the cart = 32 Kg.
Force applied to the cart = 12 N.
So, Applying the formula F = ma ,
We get , 12 = 32a
a = 0.375 m/[tex]s^{2}[/tex] (acceleration of the cart due to the force applied)
Now , as we know that s = ut + [tex]\frac{1}{2}[/tex]a[tex]t^{2}[/tex]
Where u is the initial speed which is zero here,
So, s = [tex]\frac{1}{2}[/tex](0.375)[tex](3.5)^{2}[/tex] (Since, time given is 3.5
seconds)
s = 2.297 m
Thus, distance covered by the cart will be 2.297 m .
