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A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from the impact: one travels in the air and the other in the concrete, and they are 0.90 s apart. The speed of sound in air is 343 m/s, and in concrete is 3000 m/s.How far away did the impact occur?

Respuesta :

Answer:

Distance will be 348.55 m

Explanation:

We have given speed of sound in air = 343 m /sec

And speed of sound in concrete = 3000 m/sec

Let time is t sec

It is given that 0.90 sec apart

As we know that distance will be same

And distance = speed × time

So 3000×t = 343 × (t+0.9)

[tex]3000t=343t+308.7[/tex]

t = 0.116 sec

So distance will be d = 3000 t = 3000×0.116 = 348.55 m

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