The solution is x=3 and y=4
Step-by-step explanation:
Given
[tex]10x+4y=46\ \ \ Eqn\ 1\\17x-4y=35\ \ \ Eqn\ 2[/tex]
As the coefficients of y in both equations are same i.e. 4 with already different signs, we can simply add the equations
So,
Adding Eqn 1 and Eqn 2
[tex]10x+4y+17x-4y = 46+35\\27x = 81[/tex]
Dividing both sides by 27
[tex]\frac{27x}{27} = \frac{81}{27}\\x = 3[/tex]
Putting x=3 in eqn 1
[tex]10(3)+4y = 46\\30+4y = 46\\30+4y-30 = 46-30\\4y = 16[/tex]
Dividing both sides by 4
[tex]\frac{4y}{4} = \frac{16}{4}\\y = 4[/tex]
Hence,
The solution is x=3 and y=4
Keywords: Linear equations, variables
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