Answer:
The number of dimes is 22 and the number of nickels is 8.
Step-by-step explanation:
Given:
Jaimes has $2.60 in dimes and nickels.
The number of dimes is 14 more than the number of nickels.
Now, to find the each coin he have.
Let the dimes be [tex]10D[/tex].
And the nickel be [tex]5N[/tex].
(As 1 dime = 10 cent and 1 nickel = 5 cent)
As given in question:
[tex]10D+5N=260[/tex]............(1)
[tex]D=N+14[/tex]...................(2) (The number of dimes is 14 more than number of nickels.)
Now, solving the equation (1):
[tex]10D+5N=260[/tex]
Putting the value of equation (2) on place D we get:
[tex]10(N+14)+5N=260[/tex].
[tex]10N+140+5N=260[/tex].
[tex]15N+140=260[/tex].
Subtracting both sides by 140 we get:
[tex]15N=120[/tex].
Dividing both sides by 15 we get:
[tex]N=8[/tex].
The number of nickels = 8.
And the number of dimes = (N+14) = 8+14=22.
Therefore, the number of dimes is 22 and the number of nickels is 8.
