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Given:

N2 + 3H2 → 2NH3


Bond Bond Energy (kJ/mol)

N≡N 942

H–H 432

N–H 386


Use the bond energies to calculate the change in enthalpy for the reaction.


The enthalpy change for the reaction is ____ kilojoules. Express answer in 2 sig figs

GivenN2 3H2 2NH3Bond Bond Energy kJmolNN 942HH 432NH 386Use the bond energies to calculate the change in enthalpy for the reactionThe enthalpy change for the re class=

Respuesta :

Neetoo

Answer:

ΔH = -78 kj/mol

Explanation:

Given data:

Bond energies:

N≡N = 942 kJ/mol

H-H = 432 kj/mol

N-H = 386 kj/mol

Change in enthalpy of reaction = ?

Solution:

N₂ + 3H₂  → 2NH₃

942 + 3×432   =  2(386×3)

942+1296 = 2316

2238 = 2316

ΔH = Bond broken - bond formed

ΔH = 2238  kj/mol - 2316 kj/mol

ΔH = -78 kj/mol

Answer:-78 kilojoules

Explanation:

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