The work done on the puck is 96 J
Explanation:
According to the work-energy theorem, the work done on the hockey puck is equal to the change in kinetic energy of the puck.
Mathematically:
[tex]W=K_f -K_i= \frac{1}{2}mv^2-\frac{1}{2}mu^2[/tex]
where
[tex]K_f = \frac{1}{2}mv^2[/tex] is the final kinetic energy of the puck, with
m = 2 kg being the mass of the puck
v = 10 m/s is the final speed
[tex]K_i = \frac{1}{2}mu^2[/tex] is the initial kinetic energy of the puck, with
u = 2 m/s being the initial speed of the puck
Substituting numbers into the equation, we find the work done by the player on the puck:
[tex]W=\frac{1}{2}(2)(10)^2 - \frac{1}{2}(2)(2)^2=96 J[/tex]
Learn more about work and kinetic energy:
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